On the аnswer sheet prоvided tо yоu for the exаm, or scrаp paper, complete all of the parts of the following question: Written Response Question 3 (8 pts): Mechanism – conversion of ROH to RBr with PBr3 with stereochemical inversion. In the space below show how this conversion occurs using 2-butanol as the starting material with curved arrows for the movement of electrons, proper Lewis structures and formal charges. Be sure to show how the stereochemistry is inverted. Click to Show Image Description A chemical reaction scheme showing a starting material on the left, a reagent above the arrow, and a product on the right. The starting material is 2-butanol, drawn as a four-carbon zigzag line structure. At the second carbon of the chain, a hydroxyl group (OH) is attached via a bold wedge bond, indicating it projects toward the viewer and conveying a specific configuration at that stereocenter. The reagent phosphorus tribromide is written as PBr₃ above a single-headed reaction arrow pointing to the right. The product on the right is also drawn as a four-carbon zigzag line structure. At the second carbon of the chain, a hydroxyl group (OH) is attached via a dashed bond, indicating it projects away from the viewer, conveying the opposite configuration at that stereocenter relative to the starting material.