GradePack

    • Home
    • Blog
Skip to content
bg
bg
bg
bg

Author Archives: Anonymous

A total current of 6 mA enters a parallel combination of 3 k…

A total current of 6 mA enters a parallel combination of 3 kΩ and 6 kΩ. What current flows through the 6 kΩ branch?

Read Details

Because an insulating oxide separates the gate from the chan…

Because an insulating oxide separates the gate from the channel, a MOSFET is controlled by a voltage, whereas a BJT is controlled by a current.

Read Details

The penetration depth of light in a semiconductor is:

The penetration depth of light in a semiconductor is:

Read Details

The helium–neon laser differs from Maiman’s ruby laser princ…

The helium–neon laser differs from Maiman’s ruby laser principally in:

Read Details

For an abrupt pn junction, extrapolating a plot of 1/C_dep²…

For an abrupt pn junction, extrapolating a plot of 1/C_dep² versus reverse bias back to 1/C_dep² = 0 yields:

Read Details

Silver has a Fermi energy E_F = 5.5 eV. Take m = 9.11 × 10⁻³…

Silver has a Fermi energy E_F = 5.5 eV. Take m = 9.11 × 10⁻³¹ kg and 1 eV = 1.602 × 10⁻¹⁹ J. (a) Using ½mv² = E_F, calculate the Fermi speed v_F. (b) A classical gas particle at 300 K would have an average kinetic energy of (3/2)kT = 0.0388 eV; calculate the speed corresponding to that energy the same way. (c) Compare the two speeds and explain in one or two sentences what the comparison reveals about why the classical electron gas model fails for metals. Show your work.

Read Details

A junction is fabricated with very heavy doping on both side…

A junction is fabricated with very heavy doping on both sides, giving a correspondingly narrow depletion region. Under increasing reverse bias it will most likely break down by:

Read Details

Diamond has a forbidden energy gap of about 5.5 eV. At room…

Diamond has a forbidden energy gap of about 5.5 eV. At room temperature it behaves as:

Read Details

In the free-electron model, increasing the conduction electr…

In the free-electron model, increasing the conduction electron concentration of a metal raises its Fermi energy.

Read Details

In the high-temperature Dulong–Petit limit the molar heat ca…

In the high-temperature Dulong–Petit limit the molar heat capacity of a solid approaches 3R, with R = 8.314 J mol⁻¹K⁻¹. The energy required to raise the temperature of 2.0 mol of such a solid by 50 K is closest to:

Read Details

Posts pagination

Newer posts 1 … 29 30 31 32 33 … 99,164 Older posts

GradePack

  • Privacy Policy
  • Terms of Service
Top