A wall footing has the following conditions. Determine the required development length, ld, for the reinforcement. Assume the footing is 4 ft wide, the pressure that acts on the bottom of the footing is 5,300 psf, and the reinforcement is a #5 bar spaced every 12 inches.The bottom of the footing is at a depth of 4 ft below grade.The service dead load is 7 kips/ft, and the service live load is 8 kips/ft.The wall is 16 in. thick.The footing is 10 in. thick.The allowable soil pressure, qa, is 5,300 psf.The soil has a density of 120 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 3,600 psi and fy = 60,000 psi.

A wall footing has the following conditions. Determine how much greater the factored load is than the unfactored load.The bottom of the footing is at a depth of 2 ft below grade.The service dead load is 7.5 kips/ft, and the service live load is 7 kips/ft.The wall is 10 in. thick.The footing is 15 in. thick.The allowable soil pressure, qa, is 4,900 psf.The soil has a density of 120 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 3,100 psi and fy = 60,000 psi.

A wall footing has the following conditions. Determine the minimum cross-sectional area of the reinforcement. Assume the footing is 5 ft wide and the pressure that acts on the bottom of the footing is 5,520 psf.The bottom of the footing is at a depth of 2 ft below grade.The service dead load is 15 kips/ft, and the service live load is 6 kips/ft.The wall is 14 in. thick.The footing is 12 in. thick.The allowable soil pressure, qa, is 4,800 psf.The soil has a density of 125 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 3,500 psi and fy = 60,000 psi.

Determine the required splice length for the epoxy-coated longitudinal bars in the following tied column made of lightweight concrete. Assume that some of the longitudinal bars are in tension and that the connection should be designed as a Class B contact lap splice. Use ACI 318-14 Table 25.4.2.2 to calculate the development length, and assume that the ties satisfy the Code minimum.Column width, b = 28 in.Column thickness, h = 12 in.Clear cover to ties = 1.5 in.Number of longitudinal bars = 4Size of longitudinal bars = No. 7Size of ties = No. 3Concrete strength = 3,500 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 40,000 psi

Determine the maximum axial strength φPn,max for the following circular tie column.Column diameter, h = 22 in.Number of longitudinal bars = 15Size of longitudinal bars = No. 8Size of ties = No. 3Concrete strength = 5,000 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 60,000 psi

A wall footing has the following conditions. Determine the required development length, ld, for the reinforcement. Assume the footing is 4 ft wide, the pressure that acts on the bottom of the footing is 4,900 psf, and the reinforcement is a #4 bar spaced every 12 inches.The bottom of the footing is at a depth of 3 ft below grade.The service dead load is 7 kips/ft, and the service live load is 7 kips/ft.The wall is 12 in. thick.The footing is 16 in. thick.The allowable soil pressure, qa, is 4,900 psf.The soil has a density of 130 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 3,700 psi and fy = 60,000 psi.

Determine the required splice length for the longitudinal bars in the following tied column. Assume that all of the longitudinal bars are in compression and that you will use a contact lap splice. Do not incorporate a reduction in length due to ACI 318-14 Section 10.7.5.2.1.Column width, b = 26 in.Column thickness, h = 24 in.Clear cover to ties = 1.5 in.Number of longitudinal bars = 10Size of longitudinal bars = No. 7Size of ties = No. 4Concrete strength = 8,000 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 40,000 psi

Use the interaction diagrams found in Appendix A of the textbook to determine whether the following rectangular tied column with bars in 4 faces can safely support a load of Pu = 264 kip and Mu = 0.0 kip-ft.b = 22 in.h = 12 in.fc’ = 4 ksify = 60 ksiγ = 0.75ρg = 0.04

A wall footing has the following conditions. Determine the required cross-sectional area of shrinkage and temperature reinforcement. Assume the footing is 4 ft wide, the pressure that acts on the bottom of the footing is 4,599 psf, and the reinforcement is a #8 bar spaced every 12 inches.The bottom of the footing is at a depth of 4 ft below grade.The service dead load is 6 kips/ft, and the service live load is 7 kips/ft.The wall is 12 in. thick.The footing is 13 in. thick.The allowable soil pressure, qa, is 4,000 psf.The soil has a density of 110 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 4,000 psi and fy = 60,000 psi.

A wall footing has the following conditions. Determine the depth, d, of the reinforcement. Assume the footing is 3 ft wide, the pressure that acts on the bottom of the footing is 7,066 psf, and the reinforcement is a #9 bar spaced every 12 inches.The bottom of the footing is at a depth of 5 ft below grade.The service dead load is 7 kips/ft, and the service live load is 8 kips/ft.The wall is 16 in. thick.The footing is 11 in. thick.The allowable soil pressure, qa, is 5,800 psf.The soil has a density of 130 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 3,600 psi and fy = 60,000 psi.