A solution contains 15.0 g of KBr (119.0 g/mol) dissolved in…
A solution contains 15.0 g of KBr (119.0 g/mol) dissolved in 200.0 g of water. Calculate ΔTb. (Kb water = 0.512 °C/m, assume complete dissociation) A.0.323 °CB. 0.646 °CC. 0.161 °CD. 0.512 °C moles = mass (g) ÷ molar mass (g/mol) m = moles of solute ÷ kilograms of solvent ΔTb=i⋅Kb⋅m
Read DetailsWhat mass of ethylene glycol (62.07 g/mol, i = 1) is needed…
What mass of ethylene glycol (62.07 g/mol, i = 1) is needed to lower the freezing point of 500.0 g of water by 2.00 °C? Kf water = 1.86 °C/m A.16.7 gB. 33.4 gC. 62.1 gD. 124 g ΔTf=i⋅Kf⋅m m=i⋅KfΔTf m = moles of solute ÷ kilograms of solvent Mass=moles⋅M
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