Going from room temperature, 298 K, to {T} K, the rate of a…
Going from room temperature, 298 K, to {T} K, the rate of a reaction doubles. Calculate the activation energy for the reaction in kJ/mol. R = 8.314 x 10-3 kJ/mol Answer format: Enter in standard notation, not scientific using 3 sig figs. Do not include units.
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Refer to the list of reduction potentials provided, plus the additional reduction potential for the fake element, Fa provided here. Calculate the value of E°cell. For the reaction, 2AgNO3(aq) + Fa(s) à 2Ag(s)+ Fa(NO3)2(aq) Fa2+(aq) + 2 e- à Fa(s) E°1/2 = – {E} V Answer format: Enter your answer to 2 decimal places in standard notation. Do not include the units.
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