On the answer sheet provided to you for the exam, or scrap paper, complete all of the parts of the following question: Written Response Question 6 (9 pts): Introduction to synthesis.  You now have the synthetic tools to ‘move’ functional groups such as double bonds and alkyl halides (I’m just reminding you that you know) as well as open and close rings.  In the synthetic schemes below, on your answer sheet or scrap paper, fill in the appropriate reagents and/or products for the steps where they are missing.     Click to Show Image Description A multi-step synthesis problem divided into three labeled sections, with dashed answer boxes labeled A through G indicating where students must supply either reagents, solvents, or products. The first section is labeled “Changing Stereochemistry:” and shows a two-step sequence. The starting material is a branched alcohol drawn as a zigzag carbon chain with an OH group attached via a bold wedge bond, indicating the hydroxyl projects toward the viewer and conveying specific stereochemistry at that carbon. A reaction arrow points to the right toward Box A, labeled “show reagents and or solvents,” which is blank. A second arrow then points to Box B, labeled “show product of this step,” which is also blank. A third arrow labeled NaCN above and DMF below points to a final product on the right consisting of a similarly branched carbon chain with a CN group attached via a dashed bond, indicating it projects away from the viewer. Lone pair dots are explicitly shown on the nitrogen of the CN group. The second section is labeled “Building a longer carbon structure:” and shows a two-step sequence. The starting material is a carbon chain containing an internal triple bond, shown as three parallel lines. A reaction arrow points to Box C, labeled “show reagents and or solvents,” which is blank. A second arrow points to Box D, labeled “show product of this step,” which is also blank. A third arrow labeled H₂O above and H₂SO₄ below points to a final product drawn as a branched carbon chain with a carbonyl group (C=O), representing a ketone. The third section contains two parts. The left part is labeled “Ring Closure:” and shows a starting material consisting of a branched carbon chain with a terminal double bond at one end and a bromine atom (Br) at the other end. A reaction arrow labeled H₂O above and H₂SO₄ below points to Box E, labeled “show product of this step,” which is blank. The right part is labeled “Final step is Williamson Ether:” and shows an arrow from Box E leading to Box F, labeled “show reagents and or solvents,” which is blank, followed by another arrow leading to Box G, labeled “show product of this step,” which is also blank.

On the answer sheet provided to you for the exam, or scrap paper, complete all of the parts of the following question: Written Response Question 3 (8 pts): Mechanism – conversion of ROH to RBr with PBr3 with stereochemical inversion. In the space below show how this conversion occurs using 2-butanol as the starting material with curved arrows for the movement of electrons, proper Lewis structures and formal charges.  Be sure to show how the stereochemistry is inverted.   Click to Show Image Description A chemical reaction scheme showing a starting material on the left, a reagent above the arrow, and a product on the right. The starting material is 2-butanol, drawn as a four-carbon zigzag line structure. At the second carbon of the chain, a hydroxyl group (OH) is attached via a bold wedge bond, indicating it projects toward the viewer and conveying a specific configuration at that stereocenter. The reagent phosphorus tribromide is written as PBr₃ above a single-headed reaction arrow pointing to the right. The product on the right is also drawn as a four-carbon zigzag line structure. At the second carbon of the chain, a hydroxyl group (OH) is attached via a dashed bond, indicating it projects away from the viewer, conveying the opposite configuration at that stereocenter relative to the starting material.

On the answer sheet provided to you for the exam, or scrap paper, complete all of the parts of the following question: Written Response Question 4 (8 pts): Mechanism – Addition of H2O to cyclohexene.  Be sure to indicate any relevant stereochemistry!   Click to Show Image Description A chemical reaction scheme. The starting material on the left is 1-methylcyclohexene, drawn as a six-membered ring with one double bond within the ring, shown as two parallel lines between two adjacent ring carbons. A methyl group, represented as a single line, is attached to one of the two carbons that share the double bond. Above the reaction arrow, H₂O is written, and below the arrow, H₂SO₄ is written, representing sulfuric acid as an acid catalyst. A single-headed reaction arrow points to the right. No product structure is shown.

Which of the following is NOT a laboratory finding commonly found in patients with eating disorders?

Which of the following is NOT required criteria for diagnosis of Restless Leg Syndrome?

Which of the following is NOT a characteristic of a monopolistically competitive market?

In a perfectly competitive market, individual firms are price takers and cannot influence the market price.

Which of the following statements best captures the concept of marginal analysis in decision making?

Which of these is NOT a side effect of NSAIDs?

The diagnosis of Meniere’s disease is based on all the following EXCEPT: