A random sample of the weights of dogs at a local kennel yielded the following summary information: median = 80 lb lower quartile = 70 lb upper quartile = 90 lb lighest dog = 25 lb heaviest dog = 160 lb Use this information to construct a box plot and then use the box plot to determine which one of the following statements is true.

The mean length of time required to complete the Columbus Marathon was 4.5 hours.  The standard deviation of the times was 0.50 hours.  Assume that the racing times were approximately normally distributed.  What proportion of the runners would be expected to require between 5.0 and 5.5 hours to complete the race?

Health care issues are receiving a greal deal of attention in both the academic and political arenas.  A sociologist recently conducted a survey of senior citizens whose net worth is too high to quality for Medicaid, but who have no private health insurance.  The ages (in years) of 9 uninsured senior citizens were as follows: Senior Citizen Age 1 65 2 70 3 64 4 84 5 74 6 72 7 87 8 79 9 80 Find the variance of the ages of these 9 senior citizens.

The partially completed ANOVA table for a 3 x 4 factorial experiment (i.e., there are 3 levels of factor A and 4 levels of factor B) with two replications is shown below: Source          df          SS          MS          F    Total                          18.1 Factor A                     0.8 Factor B                     5.3 A x B                           9.6 Error                                                                 Find the error sums of squares.

Find the probability of an observation lying more than z = 1.95 standard deviations above the mean.

An industrial psychologist is investigating the effects of work environment on employee attitudes.  A group of 20 recently hired sales trainees were randomly assigned to one of 4 different “home rooms” with 5 trainees per room.  Each room was identical except for the color of the walls.  The 4 colors used were light green, light blue, gray, and red.  Therefore, in this experiment the 4 treatments were the 4 room colors.  The psychologist wants to compare the mean attitudes of the trainees assigned to the 4 rooms with different colors.  At the end of the training program, the attitude of each trainee was measured on a 60 point scale (the lower the score, the poorer the attitude).  The data were subjected to an analysis of variance.  The partially completed Analysis of Variance (ANOVA) table was as follows: Source           df       SS              MS              F     Total                       1,829.75 Treatments             1,678.15 Error                          151.60                                      What are the total degrees of freedom, treatment degrees of freedom, and error degrees of freedom?

A survey was conducted to determine how people rate the quality of programming available on TV.  Twenty-one respondents were asked to rate the overall quality from 0 (no quality at all) to 100 (extremely good quality). The stem-and-leaf display based on these data (using the first digit as the stem and the second digit as the leaf) is shown below: Stem                       Leaves                                     3               2     5 4               0     3     4     7     8     9 5               1     1     2     3     4     5 6               1     2     5     6     7 7               7     8 Based on the stem-and-leaf display, the lower quartile for these TV ratings is __________.

On a particular ranch weaning weights of calves are normally distributed with a mean of 430 lb and a standard deviation of 20 lb.  Find the probability that a randomly selected calf will weigh less than 415 lb.

Find the probability of an observation lying more than z = 2.17 standard deviations above the mean.

A survey was conducted to determine how people rate the quality of programming available on TV.  Twenty-one respondents were asked to rate the overall quality from 0 (no quality at all) to 100 (extremely good quality). The stem-and-leaf display based on these data (using the first digit as the stem and the second digit as the leaf) is shown below: Stem                       Leaves                                     3               2     5 4               0     3     4     7     8     9 5               1     1     2     3     4     5 6               1     2     5     6     7 7               7     8 Based on the stem-and-leaf display, the median for these TV ratings is __________.