Consider each scenario and decide which statistical procedure should be used to answer the question. Scenario A: On average, do Stat 200 students spend more time on social media (hours/week) when compared to studying (hours/week). A difference in hours/week was computed for each student when considering the two samples.  Scenario B: On average, are the weights (in pounds) for carry-on luggage of adult male passengers higher in the winter months when compared to summer months. A random sample of 100 male passengers who traveled in the winter and a random sample of 100 males passengers who traveled in the summer were obtained.  The weight of the carry-on luggage in pounds was obtained. With Scenario A, we should use the [answer1] procedure.   With Scenario B, we should use the [answer2] procedure.

Consider the StatKey output below that provides a bootstrap distribution for the difference in proportions:   Use all provided information. The normal approximation of this bootstrap distribution is: N(

A scientific study conducted in 2017 wants to determine if a person drinking soda attracts more flies than a person drinking water.  The study looked at 62 adult volunteers who were randomly assigned to consume either soda or water. Their attractiveness to flies was measured by counting how many flies approached each person in a one-hour period.  Of the 31 adults assigned to soda group, they found that the average number of flies was 132.  With the 31 adults assigned to water group, they found the average number of flies was 130. The correct null and alternative hypotheses for this situation would be: Ho:[answer1][answer2][answer3] Ha:[answer4][answer5][answer6] Assuming the relevant p-value for this test was 0.3523, complete the conclusion below: We [answer7] the null hypothesis.  We [answer8] convincing evidence that there is a difference in the mean number of flies that were attracted when comparing soda and water drinkers.

Assume we are testing the hypotheses below, using a sample of size n=25: H0: p = 0.50   Ha: p

Assume a researcher performs a hypothesis test and uses the below screenshot from StatKey to calculate the p-value: Look at all of the provided information on the graph when answering this question.  The alternative hypothesis of Ha: [answer1] is the only possibility because the p-value was obtained from the theoretical [answer2] distribution and the test is [answer3].

Consider the three histograms shown below. Each are based on n = 900 observations.   Match the histograms to the corresponding boxplots.

A researcher wants to answer the question: Do used Subaru Foresters cost more in Washington State than they do in Tennessee, on the average?  The researcher randomly chooses 20 used Foresters for sale in Washington State and randomly chooses 20 used Foresters for sale in Tennessee. The asking price (in thousands of dollars) and state are recorded for each car. The researcher used the data to create the randomization distribution below:   Decide whether each of the statements below is true or false when considering all provided information.

Data was obtained from a randomly selected sample of n = 22 smart watch users.  These smart watch users indicated they stood for an average of 14 minutes per day with a standard deviation of 4 minutes per day. The calculated standard error of the mean is 0.85 minutes per day. Assume that all conditions are met to use the theoretical t distribution for inference. Which is the correct 99% confidence interval for the average minutes per day stood by Smart-watch users?  

Research Question:  Does the data suggest that less than 60% of Americans have at least $1000 in the bank for an emergency. The sample statistic of interest is p-hat: the proportion of Americans who do have at least $1000 in the bank for an emergency. Company A surveys 240 Americans with a sample proportion of 0.58. Company B surveys 410 Americans with a sample proportion of 0.58. Company C surveys 80 Americans with a sample proportion of 0.58. Which Company has the most evidence against the null hypothesis, i.e. in favor of the research question?

Suppose researchers surveyed 52 expecting mothers at a “Future Mothers” class on their attitudes on the use of formula vs. breastfeeding. The survey results found that 20% of expecting mothers favored the use of formula over breastfeeding.  Using 5,000 Bootstrap samples, we calculate a 95% confidence interval to be 18.6% to 21.4% . Indicate what would happen to the width of the confidence interval if the changes below were made.  For each option, assume all other quantities are held constant.