A 15.0 kg rigid rod,1.00 m in length, joins masses of 4.00 kg and 3.00 kg at each end. The combination rotates in the xy plane about a pivot through the center of the rod. If the masses are moving with a speed of 12.0 m/s, what torque applied to the system would be needed to bring the system to rest in 8.0 s? (moment of inertia of a rod pivoted about the center = 1/12 mass x length2) 2325 E4Q7.png
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