Given the following biochemical reactions, identify the organism: TSI = yellow / yellow Indole = neg Motility = pos Citrate = pos DNAse = neg MR / VP = neg / pos Moeller ornithine = purple Moeller lysine = yellow Moeller base = yellow PAD = neg

Modified Thayer-Martin agar is prepared with hemoglobin base, supplemented with enrichments and:

A foot ulcer from a diabetic patient grew oxidase negative bacilli that were lactose negative on MacConkey.  The following biochemical tests were performed:   Phenylalanine deaminase: Negative Citrate: Positive SIM: 0, 0, +  MR/VP: 0/+ Lysine decarboxylase: Negative Ornithine decarboxylase: Negative DNase: Negative ONPG: Positive Arabinose: Positive The organism should be identified as:

Match the test to the to the reagent

Match the organism with the disease it most commonly causes.

An organism is alkaline /acid on triple sugar iron agar.  This indicates that it: 1. Cannot ferment glucose 2. Ferments glucose  3. Ferments lactose or sucrose 4. Ferments sucrose 

Given the customer reviews shown below, which one of the following would correctly display the first review rating for ABC, Inc.? cust_reviews = [    {‘name’ : “XYZ, Inc.”,     ‘reviews’ : [        {‘rating’: 5, ‘comment’ : “Excellent work!”},        {‘rating’: 4, ‘comment’: “Well done!”},        {‘rating’: 3, ‘comment’: “Would recommend!”}       ]    }    ,    {‘name’: “ABC, Inc.”,     ‘reviews’: [        {‘rating’: 1, ‘comment’: “Just awful!”},        {‘rating’: 3, ‘comment’: “Could be better!”}       ]    }]

Given the variable alphabet with all 26 letters of English alphabet from a to z, what will be the result of executing the following code? k = alphabet.index(‘klm’)soup = alphabet[k:k + alphabet.index(‘fgh’)]n = soup.index(‘n’)print(alphabet[n:n+3] + soup[:2])

Assuming variables a and b are assigned to ‘THE WHOLE’ and ‘PART’, respectively, which one of the following will produce the substring ‘WHOLE’?

Given num1 = 4 and num2 = 5, what will be the value of answer variable? def pass_it(x, y):  z = x – y  result = get_result(z)  return(result) def get_result(n):  z = n + 2  return(z) answer = pass_it(num2, num1)