In a butane lighter, 1.0 mol of butane (C4H10) burns with ex…
In a butane lighter, 1.0 mol of butane (C4H10) burns with excess O2 to form CO2 and water. Find the mass of CO2 produced by this reaction. (hint: Moles = g/MW, the law of conservation of mass) (Molar mass of C4H10 – 58.12 g/mol; O2 = 32.00 g ; CO2 = 44.01 g ; H2O = 18.02 g)2C4H10 + 13O2 = 8CO2 + 10H2O
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