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A shear connection is fabricated with 3/4-in. bolts and lumb…

A shear connection is fabricated with 3/4-in. bolts and lumber that has a moisture content of 22 percent. The lumber remains above 21 percent while the connection is in service. What wet service factor, CM, should be used?

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A single-story wood-frame building is exposed to a wind load…

A single-story wood-frame building is exposed to a wind load of wU = 355 lb/ft. For simplicity, assume this load was determined from the load combinations, i.e. do not apply the load combinations to it, and that the building has no windows or doors. Let L = 52 ft, b = 30 ft, and the height of the walls be 9.5 ft. What is the unit shear in the shear walls?

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Determine the dowel bearing strength for a 3/4-in.-diameter…

Determine the dowel bearing strength for a 3/4-in.-diameter bolt in Spruce-Pine-Fir with the load applied perpendicular to grain.

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Determine the dowel bearing strength for a 5/8-in.-diameter…

Determine the dowel bearing strength for a 5/8-in.-diameter bolt in Southern Pine with the load applied perpendicular to grain.

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Use the AWC Special Design Provisions for Wind and Seismic,…

Use the AWC Special Design Provisions for Wind and Seismic, 2015 Edition and ASD procedures to answer the following question.A building with a non-structural interior wall is exposed to a transverse load of w = 345 lb/ft. The roof is sheathed with single-layer straight lumber sheathing. Is the diaphragm satisfactory in regard to the maximum diaphragm aspect ratio? Let L = 36 ft, a = 30 ft, b = 6 ft, be = 14 ft, and bi = 5 ft.

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A wood member is loaded as shown. Using ASD, determine the a…

A wood member is loaded as shown. Using ASD, determine the adjusted tension strength, Ft’. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 1,500 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 8,000 lbPE = 8,500 lbQD = 1,000 lbQL = 1,000 lbQLr = 2,000 lbQS = 3,500 lbQR = 1,000 lbQW = 0 lbQE = 0 lbSpan:L = 8 ft Member size:4 x 8 Stress grade and species:Select Structural Douglas Fir-Larch Unbraced length:lu = L/2 = 4 ft Moisture content:MC < 19 percent 

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Use the AWC Special Design Provisions for Wind and Seismic,…

Use the AWC Special Design Provisions for Wind and Seismic, 2015 Edition and ASD procedures to answer the following question.A single-story wood-frame building is exposed to a wind load of wU = 335 lb/ft. For simplicity, assume this load was determined from the load combinations, i.e. do not apply the load combinations to it, and that the building has no windows or doors. Let L = 72 ft, b = 14 ft, and the height of the walls be 8 ft. The walls are sheathed with structural fiberboard. Are the shear walls satisfactory in regard to the maximum shear wall aspect ratio?

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For columns with end conditions other than pinned end column…

For columns with end conditions other than pinned end columns, the effective unbraced length is taken as _______.

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A wood member is loaded as shown. Using ASD, determine the m…

A wood member is loaded as shown. Using ASD, determine the maximum axial stress in the member. Assume normal temperatures, no incising, and that all loads act in the directions shown. Ignore the weight of the member.Load:PD = 1,500 lbPL = 0 lbPLr = 0 lbPS = 0 lbPR = 0 lbPW = 5,500 lbPE = 5,000 lbQD = 500 lbQL = 0 lbQLr = 500 lbQS = 4,500 lbQR = 2,000 lbQW = 0 lbQE = 0 lbSpan:L = 13 ft Member size:4 x 8 Stress grade and species:No. 1 Douglas Fir-Larch Unbraced length:lu = L/2 = 6.5 ft Moisture content:MC < 19 percent 

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A wood column is pin connected at its top and bottom. Determ…

A wood column is pin connected at its top and bottom. Determine the controlling slenderness ratio, le/d, for the column. Assume normal temperatures, no incising, and that all loads are downward. Ignore the weight of the member.Load:PD = 2,000 lbPL = 4,000 lbPLr = 1,500 lbPS = 3,000 lbPR = 2,000 lbPW = 1,500 lbPE = 0 lbLength:L = 12 ftMember size:4 x 12Stress grade and species:No. 2 Douglas Fir-LarchUnbraced length:lu = L = 12 ftMoisture content:MC < 19 percent

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