Finally, with X the total number of blocks so that X = X_1 +…
Finally, with X the total number of blocks so that X = X_1 + … + X_n, calculate E(X) by completing the calculation E(X) = E(X_1) + \sum_{i=2}^n E(X_i) = … Your result should be as simplified as possible (and make sure to check that it coincides with your previous answers when n = 1, n = 2, n = 3).
Read DetailsConsider the undirected graph G given below. Now answer the…
Consider the undirected graph G given below. Now answer the following questions. (You do not need to argue for your answers. You can write an edge by its end points, like 78 or 87 for the rightmost edge.)1) What are the bridges of G, if any?(Recall that a bridge in a connected graph is an edge with the property that if it is removed, the resulting graph is not connected.) 2) Assume that G is traversed by the Depth-First Search algorithm, starting with node 1 and for each node exploring its neighbors in numerical order (for example, when exploring node 3, node 2 will be processed before node 5).List the back edges.
Read DetailsWe are given two strings of characters, represented as array…
We are given two strings of characters, represented as arrays A(1..n) and B(1..m).Our goal is to find a string, as long as possible, that is a subsequence of both (a common subsequence). Examples: for the strings “oranges” and “strawberry”, the (unique) answer is “rae” with length 3; for “goal” and “olga”, the answer is either “ga” or “oa” or “ol”. We shall solve this program using dynamic programming, and construct a table M(0..n,0..m) where each entry M(i,j) denotes the maximal length of a common subsequence of A(1..i) and B(1..j). This is done by the below code which in time Theta(nm) tabulates M and then prints in reverse a longest common subsequence; you must fill in the details. for i
Read Details