In nonseismic areas, spiral columns are used more extensively.

A wall footing has the following conditions. Determine the shear capacity, φVn, of the footing. Assume the footing is 4 ft wide, the pressure that acts on the bottom of the footing is 6,500 psf, and the reinforcement is a #4 bar spaced every 12 inches.The bottom of the footing is at a depth of 3 ft below grade.The service dead load is 11 kips/ft, and the service live load is 8 kips/ft.The wall is 12 in. thick.The footing is 13 in. thick.The allowable soil pressure, qa, is 5,700 psf.The soil has a density of 110 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 3,900 psi and fy = 60,000 psi.

Determine the location of the neutral axis, c, for the following tied column when the largest strain in the concrete is 0.003 and the strain in the tension reinforcement is 0.003.b = 14 in.h = 20 in.Clear cover to ties = 1.5 in.Number of longitudinal bars = 6Size of longitudinal bars = No. 6Size of ties = No. 3Concrete strength = 5,500 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 60,000 psi

Generally, columns are built with the same reinforcement in the two faces parallel to the axis of bending.

Misalignment of a load on a column will produce a moment.

Spiral columns tend to hold up better during seismic events compared to traditional tied columns.

Determine the required splice length for the longitudinal bars in the following tied column. Assume that all of the longitudinal bars are in compression and that you will use a contact lap splice. Do not incorporate a reduction in length due to ACI 318-14 Section 10.7.5.2.1.Column width, b = 22 in.Column thickness, h = 16 in.Clear cover to ties = 1.5 in.Number of longitudinal bars = 4Size of longitudinal bars = No. 9Size of ties = No. 3Concrete strength = 4,000 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 40,000 psi

In seismic regions, column ties are heavier and spaced further apart than ties in nonseismic regions.

A wall footing has the following conditions. Determine how much greater the factored load is than the unfactored load.The bottom of the footing is at a depth of 4 ft below grade.The service dead load is 6.6 kips/ft, and the service live load is 6.4 kips/ft.The wall is 12 in. thick.The footing is 15 in. thick.The allowable soil pressure, qa, is 4,800 psf.The soil has a density of 110 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 3,000 psi and fy = 60,000 psi.

Determine the maximum pitch, s, for the spirals in the following circular column.Column diameter, h = 28 in.Clear cover to spirals = 1.5 in.Number of longitudinal bars = 18Size of longitudinal bars = No. 7Size of spiral = No. 3Concrete strength = 2,500 psiYield strength of longitudinal bars = 60,000 psiYield strength of spiral = 60,000 psi