Which type of column reinforcement is best at preventing lateral expansion?

Compression members in concrete structures are rarely subjected to bending moments.

Determine the required splice length for the longitudinal bars in the following tied column. Assume that all of the longitudinal bars are in compression and that you will use a contact lap splice. Do not incorporate a reduction in length due to ACI 318-14 Section 10.7.5.2.1.Column width, b = 20 in.Column thickness, h = 18 in.Clear cover to ties = 1.5 in.Number of longitudinal bars = 4Size of longitudinal bars = No. 9Size of ties = No. 4Concrete strength = 4,500 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 40,000 psi

Ties restrain the longitudinal bars from buckling out through the surface of the column.

A wall footing has the following conditions. Determine the minimum width of the footing.The bottom of the footing is at a depth of 3 ft below grade.The service dead load is 14 kips/ft, and the service live load is 6 kips/ft.The wall is 16 in. thick.The footing is 12 in. thick.The allowable soil pressure, qa, is 4,200 psf.The soil has a density of 115 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 3,000 psi and fy = 60,000 psi.

Determine the required splice length for the longitudinal bars in the following tied column. Assume that all of the longitudinal bars are in compression and that you will use a contact lap splice. Do not incorporate a reduction in length due to ACI 318-14 Section 10.7.5.2.1.Column width, b = 22 in.Column thickness, h = 16 in.Clear cover to ties = 1.5 in.Number of longitudinal bars = 4Size of longitudinal bars = No. 9Size of ties = No. 3Concrete strength = 4,000 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 40,000 psi

Determine the required splice length for the uncoated longitudinal bars in the following tied column made of lightweight concrete. Assume that some of the longitudinal bars are in tension and that the connection should be designed as a Class B contact lap splice. Use ACI 318-14 Table 25.4.2.2 to calculate the development length, and assume that the ties satisfy the Code minimum.Column width, b = 22 in.Column thickness, h = 18 in.Clear cover to ties = 1.5 in.Number of longitudinal bars = 14Size of longitudinal bars = No. 10Size of ties = No. 4Concrete strength = 8,500 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 40,000 psi

A wall footing has the following conditions. Determine the critical one-way shear, Vu, at a distance of d from the face of the wall. Assume the footing is 4 ft wide, the pressure that acts on the bottom of the footing is 6,200 psf, and the reinforcement is a #7 bar spaced every 12 inches.The bottom of the footing is at a depth of 4 ft below grade.The service dead load is 10 kips/ft, and the service live load is 8 kips/ft.The wall is 14 in. thick.The footing is 11 in. thick.The allowable soil pressure, qa, is 5,100 psf.The soil has a density of 130 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 3,700 psi and fy = 60,000 psi.

A wall footing has the following conditions. Determine the critical bending moment, Mu, at the face of the wall. Assume the footing is 4 ft wide and the pressure that acts on the bottom of the footing is 5,600 psf.The bottom of the footing is at a depth of 4 ft below grade.The service dead load is 8 kips/ft, and the service live load is 8 kips/ft.The wall is 16 in. thick.The footing is 15 in. thick.The allowable soil pressure, qa, is 5,500 psf.The soil has a density of 115 lb/ft3.The concrete has a density of 150 lb/ft3.The concrete cover has a thickness of 3 in.f’c = 3,800 psi and fy = 60,000 psi.

Determine the maximum axial strength φPn,max for the following tied column.Column width, b = 24 in.Column thickness, h = 18 in.Number of longitudinal bars = 14Size of longitudinal bars = No. 8Size of ties = No. 3Concrete strength = 9,000 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 60,000 psi