Consider the following half-cell reactions: Zn2+(aq) + 2e-…
Consider the following half-cell reactions: Zn2+(aq) + 2e- ↔ Zn(s) Ecell = -0.76 V Cu2+(aq) + 2e- ↔ Cu(s) Ecell = +0.34 V If a cell is built by combining above two half-cells, what will be its cell potential? Hint: The half-cell with the highest positive potential gets reduced: Ecell= E(cathode) – E(anode)
Read DetailsIn the diagram shown, if A was Cu metal and B was Mg metal,…
In the diagram shown, if A was Cu metal and B was Mg metal, what would be the cell potential of this electrochemical cell? Use: Cu2+(aq) + 2e- = Cu(s) Ecell = +0.34 V Mg2+(aq) + 2e- = Mg(s) Ecell= -2.36 V Please open the file Question 20.docx
Read DetailsTwo half-cell reactions are shown below: Fe2+(aq) + 2e- …
Two half-cell reactions are shown below: Fe2+(aq) + 2e- ↔ Fe(s) Ecell = – 0.44 V Cu2+(aq) + 2e- ↔ Cu(s) Ecell = +0.34 V Hint: The half-cell with the highest positive potential gets reduced. the other half-cell must get oxidized. Ecell = E(cathode) – E(anode) Calculate the cell voltage of a cell built by combining above two half-cells
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