EXAM PROBLEM #5 Situation: Here is a molecular equation: 3 C…
EXAM PROBLEM #5 Situation: Here is a molecular equation: 3 Cu (s) + 2 Au(ClO3)3 (aq) –> 2 Au(s) + 3 Cu(ClO3)2 (aq) Instructions and Questions: (1) Write the answers to these two questions on your “work” page. Label them both with the question number (#5) and which part they are (A or B). A. Write the balanced total ionic equation for the reaction shown above. B. Write the balanced net ionic equation for the reaction shown above. (2) Type the answers to these two questions on your “work” page. Label them both with which part they are (C or D). C. What is oxidized in this reaction? How can you tell? Be specific. D. What is reduced in this reaction? How can you tell? Be specific.
Read DetailsEXAM PROBLEM #6 Instructions: Type your answer to the quest…
EXAM PROBLEM #6 Instructions: Type your answer to the question in the textbox below. Show all work on your “work” page. Label which problem it is (#6) Question: A 30.00 mL sample of H3BO3 solution is titrated with 0.456 M KOH solution. It takes 27.91 mL of the KOH solution to reach the endpoint. What was the molarity of the original H3BO3 solution? Reaction: H3BO3 (aq) + 3 KOH (aq) –> 3 H2O (l) + K3BO3 (aq)
Read DetailsEXAM PROBLEM #1 Instructions: Type your answers to the qu…
EXAM PROBLEM #1 Instructions: Type your answers to the questions in the textbox below. Label each answer (A, B, C). Show all work on your “work” page. Identify which problem it is (#1) Situation: 385 grams of Cu and 975 grams of HNO3 are combined and they react according to this chemical equation: 3 Cu(s) + 8 HNO3 (aq) –> 4 H2O(l) + 2 NO(g) + 3 Cu(NO3)2 (aq) Molar masses for all substances: Cu = 63.55 g/mol | HNO3 = 63.02 g/mol H2O = 18.02 g/mol | NO = 30.01 g/mol | Cu(NO3)2 = 187.57 g/mol Questions: How many grams of each of the following substances should be present at the end of the reaction? Cu HNO3 H2O
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