In the year 2014, according to salary.com, physical therapists in Jacksonville, Florida have an average annual salary of 75,000. The standard deviation is about 6,000 dollars. The distribution of salaries is right skewed. Suppose that a sample of 10 physical therapists is taken from Jacksonville, Florida. What is the sampling distribution of the sample mean?  

Suppose that you were interested in conducting a survey of Floridians and asking if they approved of the President. Suppose that you have no idea what this proportion would be, but at the end of the study you want to calculate a 95% confidence interval with a 0.025 margin of error. Find the sample size needed.

A random sample of students were asked how many hours they exercised each week. The research was interested in estimating the population standard deviation. Below are the results of bootstrapping the standard deviation. What is the 95% confidence interval for the population standard deviation using the bootstrap method?  

Forty two males were recorded on their reaction time to a stimulus. The 95% confidence interval for the population mean was (17.10, 20.34) seconds. What do we know from this confidence interval?

Find the value of t for a 99% confidence interval for the population mean when n = 19.

The average salary for an exercise specialist is $41,000. The standard deviation is about $3000. Suppose that a sample of 10 was taken, what is the approximate distribution of the sampling distribution of the sample mean?

Suppose that you wanted to estimate the population proportion of students at UF that approved of the job that what congress was doing. You decided to take a sample, but you needed to determine what size sample to take. You were uncertain what this proportion would be. You wanted to be 95% confident and to have a margin of error of 0.035. What size sample would you need?

Suppose the sampling distribution for average weight for NFL players is normally distributed with a mean of 246.9 pounds and a standard error of 7 pounds.  Find the range of central 68% of sample means.

If the p-value equals 0.001 and the alpha equals 0.05, what decision do you make?

Suppose that you took a random sample of 15 students at UF and asked them how many minutes they exercised yesterday. Suppose that you wanted to make a 90% confidence interval for the population mean. What value would you use for t?