A \(5.95~\text{g}\) sample of \(\ce{AgNO_{3}}\) is reacted w…
A \(5.95~\text{g}\) sample of \(\ce{AgNO_{3}}\) is reacted with \(\ce{BaCl_{2}}\) according to the equation $$\ce{2AgNO_{3}(aq) + BaCl_{2}(aq) -> 2AgCl(s) + Ba(NO_{3})_{2}(aq)}$$ to give \(4.37~\text{g}\) of \(\ce{AgCl}\text{.}\) What is the percent yield of \(\ce{AgCl}\text{?}\)
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