For the purposes of this question, please assume the following declarations have been made. theArray : int8[ 12 ] := [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 ];theSize : int8 := 12; Based on the implementation shown above, Pam the Programmer is trying to invoke this procedure.  Which of the following options correctly accomplish this task? A. push( theArray );mov( 0, ECX );mov( theSize, CL );push( ECX );call incrementArray; B. push( theArray );mov( 0, CX );mov( theSize, CL );push( CX );call incrementArray; C. mov( &theArray, EAX );push( EAX );mov( 0, CX );mov( theSize, CL );push( CX );call incrementArray; D. mov( &theArray, EAX );push( EAX );mov( 0, ECX );mov( theSize, CL );push( ECX );call incrementArray; E. mov( &theArray, EAX );push( [ EAX ] );mov( 0, ECX );mov( theSize, CL );push( ECX );call incrementArray; F. mov( &theArray, EAX );push( [ EAX ] );mov( 0, CX );mov( theSize, CL );push( CX );call incrementArray;

The next few questions deal with the following program and its implementation.  Some of the code is identified with line numbers that will be referenced in later questions. program StringProgram;#include( “stdlib.hhf” );#include( “cs17string.hla” ); static stringData : dword;procedure xOut( stringData : dword; searchFor : byte ); @nodisplay; @noframe;static dReturnAddress : dword; dECXRegister : dword; dEBXRegister : dword; data : byte := ‘x’; // line 1begin xOut; mov( ECX, dECXRegister ); mov( EBX, dEBXRegister ); pop( dReturnAddress ); pop( CX ); mov( CL, searchFor ); pop( stringData ); push( dReturnAddress ); push( dEBXRegister ); push( dECXRegister ); mov( stringData, EBX ); mov( data, CL );bodyLoop: mov( [ EBX ], CH ); cmp( CH, 0 ); // line 4 je endLoop; cmp( CH, searchFor ); je foundIt; jmp incEBX;foundIt: mov( CL, [ EBX ] ); jmp endLoop;   // line 2incEBX: inc( EBX ); jmp bodyLoop;endLoop: pop( ECX ); pop( EBX );ret();end xOut;begin StringProgram; stdout.put( “Please enter a string to process”, nl );mov( @size( byte ), AL );mov( 80, BL );inc( BL );mul( BL );mov( 0, EBX );mov( AX, BX );malloc( EBX );mov( EAX, stringData );mov( &stringData, EBX );push( EBX );mov( 80, CX );  push( CX );       // line 3call gets;// print the stringstdout.put( “—-> here is the string you entered: ” );push( stringData );call puts;stdout.newln();mov( &stringData, EBX );push( EBX );mov( 0, CX );mov( ‘h’, CL );push( CX );call xOut;stdout.put( “—-> here is the string after calling xOut: ” );mov( &stringData, EBX );push( EBX );call puts;stdout.newln();end StringProgram;

Line 4 originally says: mov( [ EBX + ECX ], DH );  // Line 4 For the purposes of this question only, suppose I decide to rewrite that statement as: mov( [ EBX ], DH );  // Revised Line 4 With this change in place, to make the code loop correctly and complete its task with this revised line 4, what would Line 5 need to be changed to?

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