The last line prints three values: [w] then [k] then [t].

Which constructor runs for each line?Vehicle a; runs [r1]Vehicle b(“Rust Bucket”, 2015); runs [r2]std::vector v(3); runs [r3]Vehicle d(); runs [r4]

Consider the following code. class Ticket { static int issued; int id;public: Ticket() { issued += 1; id = issued; } int getId() { return id; } static int count() { return issued; }};int Ticket::issued = 0;int nextCode() { static int code = 100; code += 5; return code;}int main() { std::cout

sum.cpp #include #include int main(int argc, char* argv[]) { int sum = 0; for (int i = 0; i < argc; ++i) { sum += std::stoi(argv[i]); } std::cout

The parameters x and y have [dur] storage duration. At Line L, ptr is [kind] pointer, and dereferencing it is [what].

Part C — Classes and Object-Oriented Programming (28 points) Consider the following code. class Tracer { std::string name;public: Tracer(std::string name) : name(name) { std::cout

roster.txt 42Albert Gator Consider the following code. std::ifstream fin(“roster.txt”);int id;std::string first;std::string second;fin >> id;std::getline(fin, first);std::getline(fin, second);std::cout

One line of main stops this program from compiling. It is [line], because [reason]. If the class were changed so that line did compile, then [cost].

After line 1, m is [m1]. After line 2, n is [n2]. The last line prints [out].

A function g has one parameter, and n is an int in the caller. Pick the way of passing that each statement describes.The call has to be written g(&n): [k1]g(n) compiles and may change n, but g(5) does not compile: [k2]The parameter is a new object holding a copy of the argument, and the function is free to change that copy: [k3]The function has to decide what to do when it is given nullptr: [k4]The best choice for a large std::vector the function only reads: no copy is made and the function cannot modify it: [k5]