Use the following information for questions 27 to 28. Wisconsin Corp. borrowed funds from Madison Inc.  Madison lent $42,000 and both parties signed an 12-month, 8% promissory note on June 30, 2025.  All principal and interest are paid at maturity.  Madison Inc. prepares financial statements as of December 31, 2025. What journal entry would Madison Inc. make regarding the interest on the note on December 31, 2025?  No prior accruals have been recorded.   Answer should be expressed as: DR (ACCOUNT NAME)  $X,XXXCR (ACCOUNT NAME)  $X,XXX No dates or explanations are needed.

You loop through a list of coupon codes. Skip the expired code “DISC0” and stop processing once you hit the “FINAL” flag.How many codes are printed by this loop? python CopyEdit codes = [‘DISC10’, ‘DISC0’, ‘DISC20’, ‘FINAL’, ‘DISC30’] for code in codes:     if code == ‘DISC0’:         continue     if code == ‘FINAL’:         break     print(code) Answer: 2 Explanation: “DISC10” is printed “DISC0” is skipped due to continue “DISC20” is printed “FINAL” triggers the break, stopping before printing “DISC30” is never reached

A coordinator needs to contact every 3rd vendor in a list of 30. If vendors are numbered from 1 to 30, which code correctly selects vendor numbers: 1, 4, 7, …? for vendor in range(1, 31, 3): print(vendor)B. for vendor in range(3, 30): print(vendor)C. for vendor in vendors: if vendor % 3 == 0: print(vendor)D. for vendor in range(0, 30, 3): print(vendor + 1) Answer: A Explanation:Option A begins at 1 and increments by 3, selecting every third vendor. B starts at 3, not 1 C selects vendors divisible by 3, not every third D would work but outputs 1, 4, 7… using an offset; A is clearer and more direct.

A store manager creates a variable: store_code = “WK94HQ” What will store_code[2] return?OPTIONS:A. 9B. WC. KD. 4 ANSWER:A. 9 EXPLANATION:Python uses zero-based indexing, so position 2 refers to the third character. In “WK94HQ”, the characters are: 0: W 1: K 2: 9

A marketing analyst is preparing a report that includes both Python code and written explanations of their findings. They want the report to be interactive and easy to share with team members via Google Drive. Which tool is best suited for this task?OPTIONS:A. Microsoft WordB. Google SheetsC. Jupyter Notebook in Google ColabD. Visual Studio Code ANSWER:C. Jupyter Notebook in Google Colab EXPLANATION:Google Colab is a cloud-based Jupyter Notebook that supports both code and markdown, making it ideal for combining analysis and explanation in a single, shareable document.

An operations analyst wants to calculate daily production totals using this function: python CopyEdit def total_output(daily_counts):     total = 0     for count in daily_counts:         total += count     return total What does the function return when called as total_output([120, 135, 150, 110])? OPTIONS: 515B. 480C. 150D. 135 ANSWER: A EXPLANATION:The function adds all the numbers: 120 + 135 + 150 + 110 = 515. This demonstrates how loops inside functions can aggregate data efficiently.

  Consider this function used by an operations analyst: python CopyEdit def reorder_notice(item, days_left):     if days_left < 3:         return item + " needs to be reordered soon."     else:         return item + " is sufficiently stocked." What is returned by reorder_notice("Printer Ink", 2)? OPTIONS: Printer Ink needs to be reordered soon.B. Printer Ink is sufficiently stocked.C. Reorder needed for Printer Ink.D. 2 needs to be reordered soon. ANSWER: A EXPLANATION:Since days_left is 2 (less than 3), the first return statement is triggered. This demonstrates how functions can use conditional logic to create context-aware responses.

A tech startup estimates that the probability of a server outage during peak hours is 0.08. What is the probability that there is not a server outage during peak hours? ANSWER: 0.92 EXPLANATION:The complement rule states that the probability of an event not occurring is 1 minus the probability of it occurring.1 – 0.08 = 0.92.

A manager uses this function to print employees eligible for promotion based on performance: python CopyEdit def eligible_for_promotion(employees):     for emp in employees:         if emp[“score”] >= 90:             print(emp[“name”], “is eligible for promotion.”) If the list passed in contains 10 employees, how many times can this function potentially print a message? OPTIONS: 0B. Between 0 and 10, depending on scoresC. Always 10D. Only once ANSWER: B EXPLANATION:The loop runs 10 times, but only employees meeting the condition (score >= 90) are printed. The actual number of messages printed depends on the input data.

A data analyst wants to make a function to label product categories. They define the function like this: def label_category(name):     print(“Product Category:”, name) Which of the following is the correct way to use this function in Python? OPTIONS: label_category = (“Office Supplies”) print(label_category(“Office Supplies”)) label_category(“Office Supplies”) def label_category(“Office Supplies”) ANSWER: C EXPLANATION:Option C correctly calls the function using its name and a string argument.Option A reassigns the function name, breaking the function.Option B works but adds an unnecessary print() call, which returns None.Option D incorrectly uses def during a call.