What is Lamarck’s model of evolution known as? Briefly explain.

Why did the Luddite protests end?

In order for technological development to occur, a practical use for the technology must first be clearly identified. 

Canvas Course Content   Protected members of a class could be made publically accessible via subclassing.

Consider the following code, and suppose the main method in Sub is executed. public class Super { private String y; public Super () { stut();} public void stut() { if (y == null) {y = “cat”;} else {y = y + y;}} } public class Sub extends Super { private String x; public Sub (String s) { x = s;} @Override public void stut() { x = x + x; } public static void main(String[] args) { Super s = new Sub(“dog”); } } Is this true or false: the stut() method in Super is invoked

Consider the following code, and suppose the main method in Sub is executed. public class Super {      private String y;      public Super () { stut();}      public void stut() {           if (y == null){              y = “cat”;          }           else {              y = “dog”;          }          System.out.println(y);    }} public class Sub extends Super {      private String x;      public Sub (String s) { x = s;}            @Override      public void stut() {         x = x + x;         System.out.println(x);      }      public static void main(String[] args) {          Super s = new Sub(“dog”);      }} What is the output?

What is the output of the code below?   class A {                public int x;                public A(int x) { this.x = x; }                public String toString() { return “x = ” + x; } }   class Super {   public A a;   public Super() {                System.out.println(“Super()”);                foo();   }   public Super (A a) {                System.out.println(“Super(A a)”);                this.a = a;                foo();   }   public void foo() {                System.out.println(“Super.foo()”);                System.out.println(a);   } }   public class Sub extends Super {   public A a;   public Sub() {                System.out.println(“Sub()”);                foo();   }   public Sub (A a) {                System.out.println(“Sub(A a)”);                this.a = a;                foo();   }   @Override public void foo() {                    System.out.println(“Sub.foo()”);                System.out.println(a);   } } public static void main(String[] args) {      new Super(new A(2)); }  

It is safer or better to use inheritance (select all correct answer(s) and no incorrect answer(s) to get credit):

What are some differences between interfaces and abstract classes in Java (select all correct answer(s) and no incorrect answer(s) to get credit)?

What are some differences between interfaces and abstract classes in Java (select all correct answer(s) and no incorrect answer(s) to get credit)?