Two half-cell reactions are shown below: Fe2+(aq)  +  2e-   ↔  Fe(s)     Ecell = – 0.44 V Cu2+(aq)  +  2e-  ↔  Cu(s)    Ecell = +0.34 V Hint: The half-cell with the highest positive potential gets reduced. the other half-cell must get oxidized. Ecell = E(cathode) – E(anode)  Calculate the cell voltage of a cell built by combining above two half-cells

A titration was carried out to find the concentration of an unknown base (NaOH) with a known concentration of HCl. Concentration of HCl =0.35 M Volume of HCl dispensed from the buret = 24.35 mL Volume of NaOH added into the beaker = 36.44 mL Calculate the number of moles of NaOH in 36.44 mL

Funeral rites that are performed without the body present are called a

Predict the products for the following reaction Zn(s)  +  2H+(aq)   →   

Identify the oxidizing agent in the following reaction Ag+(aq)   +  Al(s)  →  3Ag(s)  +  Al3+(aq)

Identify the correct statement for following reaction Zn(s)+  2Na+(aq) → Zn2+(aq)  +  2Na(s) Use: Zn2+(aq)  +  2e-  =  Zn(s)    Ecell = -0.76 V Na+(aq)  +  e-  =  Na(s)  Ecell = -2.71 V

According to the assigned reading, a floral arrangement sent by the children of the deceased is normally placed at the head end of the casket.

Identify the most acidic hydrogen in the following molecule. Please open the attached file Question-5.docx

Identify the oxidizing species in the following reaction Ag+(aq)   +  Al(s)  →  3Ag(s)  +  Al3+(aq)

Using the following two half-cells, design a spontaneous reaction and find its cell voltage Al3+(aq)  +  3e-  ↔  Al(s)            Ecell = -1.676 V Sn4+(aq)  +  2e-  ↔  Sn2+(aq)  Ecell = 0.154 v