Consider that the bacteria E-Coli will turn off its lactose…
Consider that the bacteria E-Coli will turn off its lactose operon when it has access to glucose. Which option best describes how the presence of glucose causes E-coli to turn off its lactose operon? a.) Glucose is immediately turned into ATP. This ATP then phosphorylates RNA polymerase and causes it to fall off. b.) Glucose binds to cAMP to produce ATP. Without cAMP, CAP changes shape and is unable to help RNA polymerase bind to the promoter region. c.) Glucose binds to a misshapen repressor protein. This reverts the protein back to its functional state, allowing it to bind to the operator region again and halt RNA polymerase d.) Glucose creates a different environment that causes different introns to be spliced from mRNA. This creates different proteins that are unable to break lactose down. e.) Glucose has no effect on the lactose operon.
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