One hundred eighty Americans were surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151 hours each month with a standard deviation of 32 hours. Assume the population is normally distributed. Is this a Z interval or T-interval? Construct and interpret a 95% confidence interval estimate for the population mean hours spent watching television per month.

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding. When designing a study to determine this population proportion, what is the minimum number of drivers you would need to survey to be 99% confident that the population proportion is estimated within 0.02?

The scores on a recent statistics exams are normally distributed. A random sample of 36 scores is selected and the sample mean is found to be 68. Suppose the population standard deviation is 5 points. Is this a Z-interval or a T-interval? Find a 95% confidence interval estimate for the population mean exam score. Interpret the interval.

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Find the derivative.s = t7 tan t –

Find the derivative.s = t6 cos t – 12t sin t – 12 cos t

Find the derivative of the function.y = cos4(t – 11)

Find y “.y = 6 sin(3x + 7)

Find an equation of the tangent line at the indicated point on the graph of the function.y = f(x) = x2 – x, (x, y) = (2, 2)

Find the derivative of the function.q = cos