Alternate span loading is the common loading pattern for determining maximum negative moments at supports due to live load.

A classmate has suggested a beam design that has dimensions of b = 16 in., h = 22 in., and d = 19.5 in. and is reinforced with 4 No. 7 bars. Assuming a cover of 1.5 in. and a stirrup diameter of 0.5 in., does the reinforcement fit within a single row as suggested?

Concrete forms should generally be chosen to allow for maximum reuse of the forms.

Determine As,min for the following beam given that f’c = 5,750 psi and fy = 60,000 psi.

The moment-curvature relationship is linear up to the cracking point and is referred to as the uncracked-elastic range.

You are considering a beam design that has dimensions of b = 14 in., h = 30 in., and d = 27.5 in. The beam is singly reinforced with all of the reinforcement in a single row. The concrete strength is 10,000 psi, and the yield strength of the reinforcement is 60,000 psi. What cross-sectional area of reinforcement is needed to achieve a strain in the reinforcement of 0.0075?

A beam has dimensions of b = 18 in., h = 28 in., and d = 25.5 in. and is reinforced with 4 No. 7 bars. The concrete strength is 8,200 psi, and the yield strength of the reinforcement is 60,000 psi. If the depth to the neutral surface is c = 1.76581 in., determine the strain in the reinforcement.

A beam has dimensions of b = 16 in., h = 28 in., and d = 25.5 in. and is reinforced with 3 No. 8 bars. The concrete strength is 6,400 psi, and the yield strength of the reinforcement is 60,000 psi. Determine the strength Mn for this beam.

A beam has dimensions of b = 14 in., h = 26 in., d’ = 2.5 in., and d = 23.5 in. It is reinforced with 2 No. 5 bars on the compression side and 5 No. 8 bars on the tension side. The concrete strength is 3,700 psi, and the yield strength of the reinforcement is 60,000 psi. For the results given below, determine the strength Mn for this beam.a = 4.75 in. (depth of concrete stress block)Cc = 207.2 kips (compressive force in concrete)Cs = 29.8 kips (compressive force in steel)T = 237.0 kips (tensile force in steel)

Ductility is the name given to a sample’s ability to deform beyond its yield point without a significant loss of strength.