34. The health care provider has ordered amoxicillin suspens…
34. The health care provider has ordered amoxicillin suspension 210 mg PO BID (by mouth twice daily) for a diabetic patient with a foot infection. Amoxicillin suspension is available in a concentration of 125 mg/5 mL. How many milliliters should the nurse administer for the morning dose? Round to the nearest tenth and label your answer.
Read Details38. A client with a history of gastric esophageal reflux dis…
38. A client with a history of gastric esophageal reflux disease (GERD) has been taking an antacid. The client has been seriously exceeding the dose prescribed for the condition. Which of the following is the most serious complication of exceeding the dose prescribed?
Read DetailsWhich one of the following will change the value of an equil…
Which one of the following will change the value of an equilibrium constant? A) adding other substances that do not react with any of the species involved in the equilibrium B) varying the initial concentrations of reactants C) changing temperature D) varying the initial concentrations of products E) changing the volume of the reaction vessel ENTER THE LETTER CORRESPONDING TO YOUR SELECTION IN THE SPACE PROVIDED.
Read DetailsThe balanced equation for the reaction of nitrogen dioxide a…
The balanced equation for the reaction of nitrogen dioxide and fluorine is 2 NO2 + F2 → 2 NO2F The proposed mechanism is step 1: NO2 + F2 → NO2F + F (slow)step 2: F + NO2 → NO2F (fast) Which of the following are correct? ENTER THE LETTER CORRESPONDING TO YOUR SELECTION IN THE SPACE PROVIDED. I. The mechanism supports an experimentally determined rate law of rate = k[NO2]2[F2]II. F is an intermediateIII. The reaction is first order in F2 a. I, II, and IIIb. II and III onlyc. I and II onlyd. I and III onlye. I only
Read DetailsConsider the reaction and its rate law given below for the n…
Consider the reaction and its rate law given below for the next four questions. 2 A(g) + B(g) → C(g)rate = k[A]2[B] At the beginning of one trial of this reaction[A] = 4.0 M and [B] = 1.0 M The rate of formation of C was 0.048 mole L−1 sec−1 ENTER THE LETTER CORRESPONDING TO YOUR SELECTION IN THE SPACE PROVIDED. The numerical value of k, the rate constant, for this reaction is closest to a. 3 × 10−3b. 1 × 10−2c. 8 × 10−1d. 4 × 100e. 3 × 102 Which is the label for k, the rate constant?a. L2 mol−1 sec−1b. L2 mol−2 sec−1c. L2 mol−2sec−2d. L mol−1 sec−1e. mol2 L−2 sec−1 16. When [B] decreases 0.4 M, what will be the value of [A]?a. 1.6 Mb. 3.6 Mc. 0.8 Md. 2.8 Me. 3.4 M 17. Which of the following describes how the rate for this trial reaction, at constant temperature, changes as [B]approaches 0.4 mol L−1? a. The rate remains the same because the rate constant remains the same.b. The rate remains the same because the temperature remains the same.c. The rate decreases because the concentration of the reactants decreases.d. The rate decreases because the concentration of the products increases.e. The rate remains the same because the energy of activation remains the same.
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