clc; clear;x = 0;ii = 3;for ii = 1:1:ii    ii = 2;    jj = 1;    while ii>jj        x = ii+jj;        jj = ii;    end    fprintf(‘%g%g’, ii,x)end

clc; clear;a = 0;for i = 0:1:3   a = i * i;    for i = 0:1:2        fprintf(‘%d’,a*i);        break;        fprintf(‘%d’,a+i);    end    continue;end

clc; clear;x = 7;while x > 4   for jj = 2:-2:3      if x >= 3         break;      end   end   for xx=2:2:3      if xx < 3         fprintf('%g', xx);         x = x - 3;      end   end   x = x - 2;   fprintf('%g', x+xx);end

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Identify and correct all the mistakes in the following code snippet The program calculates and displays the total value of the following series with 100 terms if you cannot see the image the series is: You cannot add whole new lines of code. To write your response, mention the line number followed by the incorrect code in the line and then the correct code. For example: Line 5: for ii=1:1:n should be for ii=1:1:100000 (this is just an example!) clc;clear var=2; num=5; den=1; ii=0; while ii

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