Going from room temperature, 298 K, to {T} K, the rate of a…
Going from room temperature, 298 K, to {T} K, the rate of a reaction doubles. Calculate the activation energy for the reaction in kJ/mol. R = 8.314 x 10-3 kJ/mol Answer format: Enter in standard notation, not scientific using 3 sig figs. Do not include units.
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