The equilibrium constant, Kc = 9.10 x 10-2, for the reaction…
The equilibrium constant, Kc = 9.10 x 10-2, for the reaction below at 298 K. X + Y à 2Z What is the value of ∆G in kJ when [X] = {x} M, [Y] = .0100 M, [Z] = .0100 M R = 8.314 J/K·mol. ∆G = R T ln(Q/K) Hint: pay attention to units Answer format: Enter in standard (not scientific) notation with 3 sig figs in kJ. Do not enter the units.
Read Details