The following question refers to a country with five states. There are 240 seats in the legislature, and the populations of the states are given in the table below. State A B C D E Population  (in thousands) 427 754 4389 3873 157 Under Jefferson’s method and a modified divisor = 39,540, the apportionments to each state areState A: [STATEA] State B: [STATEB] State C: [STATEC] State D: [STATED] State E: [STATEE]

Determine whether any of the listed candidates has a majority.Four candidates running for senate receive votes as follows:Edwards: 101,736 Fong: 39,564 Goodman: 16,956 Haddad: 28,260

Find the standard divisor for the given situation. Round your answer to two decimals.A university has 29 scholarships to be apportioned among the engineering students based on the enrollment in each department. There are three departments – Mechanical Engineering (M), Electrical Engineering (E), and Civil Engineering (C). The number of students in each department is given in the following table. Department M E C Enrollment 233 297 153  

For the apportionment of 30 seats among four states, the standard quotas are as shown in the following table. State A B C D Standard Quota 8.28 8.50 7.14 6.09 Create an extended table by giving each state’s upper quota and lower quota. State A B C D Standard Quota 8.28 8.50 7.14 6.09 Upper Quota [aupper] [bupper] [cupper] [dupper] Lower Quota [alower] [blower] [clower] [dlower]

Solve the problem.A mother wishes to distribute 11 pieces of candy among her three children (Abe, Betty, and Cindy) based on the number of hours each child spends doing chores around the house. Using a certain apportionment method, she has determined that (based on 703 minutes work for Abe, 243 minutes work for Betty, and 54 minutes work for Cindy) that Abe is to get 8 pieces of the candy, Betty is to get 3 pieces, and Cindy is to get 0 pieces. However, just before she hands out the candy, she discovers that she forgot to include 86 minutes of work that Abe did, 12 minutes of work that Betty did, and 2 minutes of work that Cindy did. When she reapportions the 11 pieces of candy using the corrected times and using the same apportionment method, Abe ends up with 8 pieces, Betty with 2 pieces, and Cindy with 1 piece. This is an example of

A country is made up of four regions A, B, C, and D. The population of each region, in thousands, is given in the following table. Region A B C D Total Population (in thousands) 512 630 483 615 2240 According to the country’s constitution, the congress will have 40 seats, divided among the four regions according to their respective populations.Find the standard quota for each region. Round to the nearest hundredth. Region A B C D Standard Quota (in thousands) [ASQ] [BSQ] [CSQ] [DSQ]

Use the preference table to answer the following questions.The preference table shows the results of a straw vote among three candidates, A, B, and C.  Number of Votes  7 6 3 1st Choice  A B B 2nd Choice  B C A 3rd Choice  C A C (a) Using the plurality-with-elimination method, which candidate wins the straw vote? [WINNER1](b) In the actual election, the 3 voters in the last column who voted B, A, and C, in that order, change their votes to A, B, C. Using plurality-with-elimination method, which candidate wins the actual election? [WINNER2](c) Is the monotonicity criterion satisfied? [YESORNO]

Determine whether any of the listed candidates has a majority.Four candidates running for congress receive votes as follows: Alberts: 44,935 Brown: 12,255 Cassimatis: 32,680 D’Amico: 28,595

Determine whether the specified paradox occurs.In a small country consisting of 5 provinces, 300 federal judges are apportioned according to the population of each province. The population of each province is shown for the years 1995 and 2000. Province A B C D E 1995 Population 25,312 8911 11,451 33,611 15,932 2000 Population 26,011 9732 12,678 35,977 17,311 Does the population paradox occur using Hamilton’s method of apportionment?

For an election with 4 candidates (A, B, C, and D), we have the following preference schedule: Number of Votes  20 14 8 7 2 1st Choice  A C D C D 2nd Choice  B B B D A 3rd Choice  C D A B B 4th Choice D A C A C Which candidate wins in the pairwise comparison between candidate A and candidate D?