When a 1.397 g sample of thymol, C10H14O(s) (a preservative)…
When a 1.397 g sample of thymol, C10H14O(s) (a preservative), is burned in a bomb calorimeter. The temperature increase from 20.00 °C to 31.23 °C, and the heat capacity of the bomb calorimeter is 4.68 kJ/°C. What is the heat of combustion of thymol, expressed in kilojoules per mole of C10H14O?
Read DetailsWrite the condensed (short form) electron configuration for…
Write the condensed (short form) electron configuration for Fr:( Make sure to follow the order following the Aufbau principle. Do not consider exceptions. Do not use superscripts, do not write the brackets on the noble gas. Use the following format Ne – 3s2 ….)
Read DetailsGiven the data: N2H4(l) + O2 (g) → N2(g) + 2 H2O (l)…
Given the data: N2H4(l) + O2 (g) → N2(g) + 2 H2O (l) ΔH° = – 622.2 kJ 2 H2(g) + O2 (g) → 2H2O (l) ΔH° = -571.6 kJ H2(g) + O2 (g) → H2O2(l) ΔH° = – 187.8 kJ using Hess’s Law the ∆H for the reaction below is [a] kJ:N2H4 (l) + 2 H2O2 (l) → N2(g) + 4 H2O (l)Must show your work (scratch paper) to receive credit.
Read DetailsGiven the following equations and ∆H° values: …
Given the following equations and ∆H° values: OF2(g) + H2O(l) → O2(g) + 2 HF(g) ∆H° = -276.6 kJ SF4(g) + 2 H2O(l) → 4 HF(g) + SO2(g) ∆H° = -827.5 kJ S(s) + O2(g) → SO2(g) ∆H° = -296.9 kJ determine the heat of reaction (kJ) at 298 K for the reaction: 2 OF2(g) + 2 S(s) →SO2(g) + SF4(g) Must show your work (scratch paper) to receive credit.
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