Determine the adequacy of a wood floor joist (2 x 10’s @ 16″…
Determine the adequacy of a wood floor joist (2 x 10’s @ 16″ o.c.) supporting a dead load (DL) = 10 psf and live load (LL) = 40 psf. The length of each floor joist between supports is 14 feet. Assume that the allowable stresses for the Hem-Fir No. grade material are as follows: Fb = 1150 psi, Fv = 75 psi. The table of relevant properties is given below. To solve the problem, fill in the blanks of each solution step provide below. Where choices are provided, select the one closest to your calculated values. Solution Steps: A = [BLANK-1] in2 Sx = [BLANK-2] in3 Uniformly distributed load (UDL) on each floor joist = [BLANK-3] lb/ft length (chose your answer from these values: 33 or 67 or 100) Maximum shear force, Vmax = [BLANK-4] lb (chose your answer from these values: 469 or 700 or 234) Maximum bending moment, Mmax (note: pay attention to units) = [BLANK-5] ft-lb (chose your answer from these values: 3284 or 821 or 1624) Actual maximum shear stress, fv-max = [BLANK-6] psi (chose your answer from these values: 51 or 81 or 101) Is it adequate in shear? [BLANK-7] (yes or no) Actual maximum bending stress, fb-max = [BLANK-8] psi (chose your answer from these values: 1521 or 921 or 1221) Is it adequate in bending? [BLANK-9] (yes or no) Picture15.jpg
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