Consider the following statement: 9+14+19+80+…+(5n+4)=n2(5n+13){math:9+14+19+80+…+(5n+4)=n2(5n+13)}Given the following possible steps for proof by math induction: Show 9+14+19+80+…+(5(n+1)+4)=(n+1)2(5(n+1)+13){math:9+14+19+80+…+(5(n+1)+4)=(n+1)2(5(n+1)+13)} must be true. Show 9+14+19+80+…+(5n+4)=n2(5n+13){math:9+14+19+80+…+(5n+4)=n2(5n+13)} must be a natural number. Suppose 9+14+19+80+…+(5n+4)=n2(5n+13){math:9+14+19+80+…+(5n+4)=n2(5n+13)} is true. Using logical deduction show 9+14+19+80+…+(5n+4)=n2(5n+13){math:9+14+19+80+…+(5n+4)=n2(5n+13)} must be true. Show 9+14+19+80+…+(5n+4)=n2(5n+13){math:9+14+19+80+…+(5n+4)=n2(5n+13)} must be positive. Show 9+14+19+80+…+(5n+4)=n2(5n+13){math:9+14+19+80+…+(5n+4)=n2(5n+13)} holds for n=1 . Indicate which of the following orders best provides a proof by math induction:

If (4, –3) is a point on the terminal side of an angle β, then sin⁡ β{math:sin⁡ β}=

If f(x) = x2- 4{“version”:”1.1″,”math”:”<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>f</mi><mo>(</mo><mi>x</mi><mo>)</mo><mo> </mo><mo>=</mo><mo> </mo><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mo> </mo><mn>4</mn></math>”} and x≥0{math:x≥0} then f−1(x)={math:f−1(x)=}

(1 + i)8 =

If h(x)=3(x2+7)−2x{math:h(x)=3(x2+7)−2x}, find h(h−1(9)){math:h(h−1(9))}

sin&ApplyFunction;2167π4+cos&ApplyFunction;2167π4={math:sin&ApplyFunction;2167π4+cos&ApplyFunction;2167π4=}

The sum of the first 16 terms of the following sequence is 4, 7, 10, 13, . . .

Solve: 34x+1−5=22{math:34x+1−5=22}

sin&ApplyFunction;2167π4+cos&ApplyFunction;2167π4={math:sin&ApplyFunction;2167π4+cos&ApplyFunction;2167π4=}

Solve this triangle. Angle C is the right angle, a = 308, A = 59.67°. To the nearest unit, length b is what?