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This is a tracing problem. Given that the following function…

Posted byAnonymous June 11, 2025June 13, 2025

Questions

This is а trаcing prоblem. Given thаt the fоllоwing functions are defined below and lines 2 and 3 are run in the Command Window, fill in the blanks on each line with the value of the variable indicated in the comments. Note: Indicate vectors of characters by placing single quotes around them. Indicate vectors of logicals by placing brackets around zeros and ones for true and false respectively. Indicate vectors of numbers by placing brackets around the numbers in the vector. 1     %Command Window Scope2     a = 'AbCdEf-02';    %The last two characters in this vector are zero and one3     c = gamma(a)    % The value stored in c after this line has run is [ans1]4     function c = gamma(a)5         a    % The value stored in a after this line has run is [ans2]6         a = delta(a)     % The value stored in a after this line has run is [ans3]7         b = strfind(a,'-')    % The value stored in b after this line has run is [ans4]8         c = zeta(a(b+1:end))    % The value stored in c after this line has run is [ans5]9         d = a(1:b-1)    % The value stored in d after this line has run is [ans6]10       d([1, 3, 5]) = 'hit'    % The value stored in d after this line has run is [ans7]11       d(2:2:end) = []    % The value stored in d after this line has run is [ans8]12       c = [upper(d) num2str(c)]    % The value stored in c after this line has run is [ans9]13    end14    function b = delta(b)15        b    % The value stored in b after this line has run is [ans10]16        c = (b=='A') | (b=='C') | (b=='E')    % The value stored in c after this line has run is [ans11]17        b(c) = b(c)+32    % The value stored in b after this line has run is [ans12]18    end19    function c = zeta(b)20        b    % The value stored in b after this line has run is [ans13]21        c = double(b(1))    % The value stored in c after this line has run is [ans14]22        c = c + str2num(b(2))    % The value stored in c after this line has run is [ans15]23    end

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