Solve the problem.Three bacteria are placed in a petri dish. The population will double every day. The formula for the number of bacteria in the dish on day t is N(t) = 3(2)t, where t is the number of days after the three bacteria are placed in the dish. How many bacteria are in the dish eight days after the three bacteria are placed in the dish?

Solve the equation.4x =

The function f is one-to-one. Find its inverse.f(x) = x2 + 5, x ≥ 0

Factor.x2 + 7x – 30

Subtract.(4×5 + 20×2 + 18) – (-2×2 + 7×5 + 14)

Collect like terms.6×8 + 9×8 – 3×8

Add or subtract. Then simplify by collecting like radical terms, if possible. Assume that no radicands were formed by raising negative numbers to even powers.-6 – 9 + 9

Factor completely.25k2 – 169m2

Solve.4×2 + 6x = – 1

Multiply.(x + 12)(x + 11)