Consider the one-way ANOVA results below, which compare down…
Consider the one-way ANOVA results below, which compare download times of three different types of computers: Anova: Single Factor SUMMARY Groups Count Sum Average Variance MAC 10 1606 160.6 508.0444444 iMAC 10 1831 183.1 188.1 Dell 10 2560 256 214.6666667 ANOVA Source of Variation SS Df MS F P-value F crit Between Groups 49739.4 2 24869.7 81.9150086 3.42516E-12 3.354130829 Within Groups 8197.3 27 303.6037037 Total 57936.7 29 Without knowing actual Tukey range results, the alternate hypothesis for the ANOVA is:
Read DetailsLet the regression equation be given by yL=78-32x{“version”:…
Let the regression equation be given by yL=78-32x{“version”:”1.1″,”math”:”yL=78-32x”}, where x{“version”:”1.1″,”math”:”x”} represents the number of hours spent partying and yL{“version”:”1.1″,”math”:”yL”} represents the predicted grade on the final exam. What is the appropriate interpretation of the slope in this scenario?
Read DetailsConsider the one-way ANOVA results below, which compare down…
Consider the one-way ANOVA results below, which compare download times of three different types of computers: Anova: Single Factor SUMMARY Groups Count Sum Average Variance MAC 10 1606 160.6 508.0444444 iMAC 10 1831 183.1 188.1 Dell 10 2560 256 214.6666667 ANOVA Source of Variation SS Df MS F P-value F crit Between Groups 49739.4 2 24869.7 81.9150086 3.42516E-12 3.354130829 Within Groups 8197.3 27 303.6037037 Total 57936.7 29 After applying the Tukey-Kramer procedure in this case, assume that the partial results show: Absolute Std. Error Critical Comparison Difference of Difference Range Results Group 1 to Group 2 22.5 5.5100245 27.55 Means are not different Group 1 to Group 3 95.4 5.5100245 27.55 Means are different Group 2 to Group 3 72.9 5.5100245 27.55 Means are different In this specific case, we conclude what in terms of mean downloading times?
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