Compute the axial compressive strength Pn and moment capacity Mn of the following tied column when the largest strain in the concrete is 0.003 and the strain in the tension reinforcement is 0.003. Note that you should not include φ in the answer and that you should not consider Pn,max.b = 14 in.h = 22 in.Clear cover to ties = 1.5 in.Number of longitudinal bars = 6Size of longitudinal bars = No. 7Size of ties = No. 3Concrete strength = 5,000 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 40,000 psi

A point inside an interaction diagram represents a combination of P and M that will cause failure.

Reinforced concrete is not elastic and has a compressive strength that is much higher than its tensile strength.

Determine the maximum axial strength φPn,max for the following tied column.Column width, b = 22 in.Column thickness, h = 26 in.Number of longitudinal bars = 12Size of longitudinal bars = No. 10Size of ties = No. 4Concrete strength = 7,500 psiYield strength of longitudinal bars = 60,000 psiYield strength of ties = 60,000 psi

The minimum number of longitudinal bars in a rectangular column is four.

Determine the maximum pitch, s, for the spirals in the following circular column.Column diameter, h = 22 in.Clear cover to spirals = 1.5 in.Number of longitudinal bars = 16Size of longitudinal bars = No. 8Size of spiral = No. 4Concrete strength = 5,500 psiYield strength of longitudinal bars = 60,000 psiYield strength of spiral = 60,000 psi

Determine the maximum pitch, s, for the spirals in the following circular column.Column diameter, h = 18 in.Clear cover to spirals = 1.5 in.Number of longitudinal bars = 6Size of longitudinal bars = No. 10Size of spiral = No. 4Concrete strength = 5,000 psiYield strength of longitudinal bars = 60,000 psiYield strength of spiral = 60,000 psi

When designing columns, it is often more desirable to use symmetrical reinforcement.

Use the interaction diagrams found in Appendix A of the textbook to determine whether the following rectangular tied column with bars in 2 faces can safely support a load of Pu = 1,320 kip and Mu = 645.3 kip-ft.b = 20 in.h = 22 in.fc’ = 4 ksify = 60 ksiγ = 0.6ρg = 0.03

Use the interaction diagrams found in Appendix A of the textbook to determine whether the following circular spiral column can safely support a load of Pu = 704 kip and Mu = 160.8 kip-ft.h = 16 in.fc’ = 4 ksify = 60 ksiγ = 0.9ρg = 0.04