The isotopic dating of igneous rocks that cross-cut sedimentary layers makes it possible to determine __________ age for boundaries between geologic periods.

When you are ready to finish the exam, please show both sides of each piece of scratch paper (even if you did not end up using it) to the camera. Thank you. NOTE: This is the end of the exam, if you press “SUBMIT” below, the exam will end. 

Is there a statistically significant relationship between overall satisfaction and store district? Determine yes or no and what is the p value? 

Using the frequency table created in the question above, add a column to the frequency table, and compute the percent. What percent of the respondents visited the park in the winter? Be sure to have the frequency table visible on your spreadsheet for when you submit the spreadsheet below. 

With the bucketed questions, is there a statistically significant relationship between satisfaction overall and satisfaction with cleanliness. Determine yes or no and what is the p value? 

Looking at the association between bucketed satisfaction overall and bucketed satisfaction with cleanliness, what percent of the respondents are satisfied with cleanliness and satisfied overall? 

Qualtrics For this portion of the test, use the Q-grocery store survey data used in class and for Week 6 homework.  If you have already imported the survey and data for class and your homework, you do not need to import it again. Open the links to Qualtrics in another tab do not exit this exam.  The survey file: Q_Grocery_Survey.qsf.  The data file: Q_Grocery_Data.csv  (If unsure how to import, basic directions are provided in the exam instructions)

Which of the following was a critical advantage for the Union that contributed to its ultimate victory?

Consider Algorithm 1 and the input array \(A\) below. \(A\) is a square matrix. \[\begin{array}{l}\textbf{Algorithm 1} \,\, processSquareMatrix(A, n): \\\quad s = \sqrt n\\\quad \textbf{for} \, i = 1\, \textbf{to} \,s \, \textbf{do}\\\quad \quad \textbf{for} \, j = 1\, \textbf{to} \, \lfloor s/2 \rfloor \, \textbf{do}\\\quad \quad \quad temp = A[i][j]\\\quad \quad \quad A[i][j] = A[i][s-j+1]\\\quad \quad \quad A[i][s-j+1] = temp\\\end{array}\] 22 17 9 76 55 61 29 83 2 45 90 22 23 42 44 3 \[ \lfloor x \rfloor \, \text{is the floor of} \, x .  n \text{ is the number of items in } A \] Enter the values of the first row of \(A\) after running the algorithm and passing \(A\) as the first parameter, and \(n\) as the second parameter: Briefly explain what this algorithm does in simple terms: Using the proper asymptotic notation, the running time of Algorithm 1 is )

Consider Algorithm 1 and the input array \(A\) below. \(A\) is a square matrix. \[\begin{array}{l}\textbf{Algorithm 1} \,\, processSquareMatrix(A, n): \\\quad s = \sqrt n\\\quad \textbf{for} \, i = 1\, \textbf{to} \,s \, \textbf{do}\\\quad \quad \textbf{for} \, j = 1\, \textbf{to} \, \lfloor s/2 \rfloor \, \textbf{do}\\\quad \quad \quad temp = A[i][j]\\\quad \quad \quad A[i][j] = A[i][s-j+1]\\\quad \quad \quad A[i][s-j+1] = temp\\\end{array}\] 22 17 9 76 55 61 29 83 2 45 90 22 23 42 44 3 \[ \lfloor x \rfloor \, \text{is the floor of} \, x .  n \text{ is the number of items in } A \] Enter the values of the first row of \(A\) after running the algorithm and passing \(A\) as the first parameter, and \(n\) as the second parameter: Briefly explain what this algorithm does in simple terms: Using the proper asymptotic notation, the running time of Algorithm 1 is )